Решите уравнение 2 cos 2x+1=(4 cos 2x+2)sin 2x
2 cos 2x+1=2 sin 2x*(2 cos 2x+1)
(2 cos 2x+1) - 2 sin 2x*(2 cos 2x+1) = 0
(2 cos 2x+1) * (1-2 sin 2x) = 0
2 cos 2x=-1 2 sin 2x=1
cos 2x=-1/2 sin 2x = 1/2
2x1=2П/3+2Пn 2x1=П/6+Пn
2x2= -2П/3+2Пn 2x2=5П/6+Пn
x1=П/3+Пn x1=П/12+Пn/2
x2= -П/3+Пn x2=5П/12+Пn/2
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Answers & Comments
2 cos 2x+1=2 sin 2x*(2 cos 2x+1)
(2 cos 2x+1) - 2 sin 2x*(2 cos 2x+1) = 0
(2 cos 2x+1) * (1-2 sin 2x) = 0
2 cos 2x=-1 2 sin 2x=1
cos 2x=-1/2 sin 2x = 1/2
2x1=2П/3+2Пn 2x1=П/6+Пn
2x2= -2П/3+2Пn 2x2=5П/6+Пn
x1=П/3+Пn x1=П/12+Пn/2
x2= -П/3+Пn x2=5П/12+Пn/2