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dianaraldugina
@dianaraldugina
July 2022
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Решите уравнение!
2 соs^2x+cos2x=0
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Answers & Comments
Maksim123451
Cos2x(2cosx+1)
cos2x=0
x= Pi/2+Pin,n z
2cosx+1=0
2cosx=-1
cosx=-1/2
x=+- arccos(-1/2)+2pin n z
x=+- (Pi-arccos(1/2)) + 2Pin n z
x=+- (Pi-Pi/3)+2pin n z
x=+-(3Pi/3-Pi/3)+2Pin n z
x=+- 2Pi/3+2Pin n z
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Answers & Comments
cos2x=0
x= Pi/2+Pin,n z
2cosx+1=0
2cosx=-1
cosx=-1/2
x=+- arccos(-1/2)+2pin n z
x=+- (Pi-arccos(1/2)) + 2Pin n z
x=+- (Pi-Pi/3)+2pin n z
x=+-(3Pi/3-Pi/3)+2Pin n z
x=+- 2Pi/3+2Pin n z