5х-7=0 или 1+х=0
х=7/5 или х=-1
2(5x+5x2-7-x)=0
10x2-4x-14=0
5x2-2x-7=0
D=144, 12
x1=(2+12)/10=1.4
x2=(2-12)/10=-1
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Answers & Comments
5х-7=0 или 1+х=0
х=7/5 или х=-1
2(5x+5x2-7-x)=0
10x2-4x-14=0
5x2-2x-7=0
D=144, 12
x1=(2+12)/10=1.4
x2=(2-12)/10=-1