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natali868686
@natali868686
July 2022
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Решите уравнение: (2х-7)^2-7(7-4х)=0 и еще одно:(х-5)^2+5(2х-1)=0
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veretenni
(2х-7)^2-7(7-4х)=0
(2x-7)
²+7(4x-7)=0
(4x²-28x+49)+(28x-49)=0
4x²-28x+49+28x-49=0
4x²=0
x²=0÷4
x²=0
x=0
(х-5)^2+5(2х-1)=0
(x
²-10x+25)+5(2x-1)=0
(x²-10x+25)+(10x-5)=0
x²-10x+25+10x-5=0
x²+20=0
x²=-20
3 votes
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CSGOandDOTA2
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veretenni
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veretenni
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Answers & Comments
(2x-7)²+7(4x-7)=0
(4x²-28x+49)+(28x-49)=0
4x²-28x+49+28x-49=0
4x²=0
x²=0÷4
x²=0
x=0
(х-5)^2+5(2х-1)=0
(x²-10x+25)+5(2x-1)=0
(x²-10x+25)+(10x-5)=0
x²-10x+25+10x-5=0
x²+20=0
x²=-20