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GaLya20013
@GaLya20013
July 2022
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Решите уравнение:
2(х+3)(х-2)-(2х+1)(х-3)-7=0
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Asqx
2(х^2-2х+3х-6)-(2х^2-6х+х-3)-7=0
2х^2-4х+6х-12-2х^2+6х-х+3 -7=0
8х-16=0
8х=16
х=2
0 votes
Thanks 1
SUPERmaner
2(x^2-2x+3x-6)-(2x^2-6x+x-3)-7=0
-2x-12-6x+x+3-7=0
-7x=-16
x=16/7
1 votes
Thanks 1
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Answers & Comments
2х^2-4х+6х-12-2х^2+6х-х+3 -7=0
8х-16=0
8х=16
х=2
-2x-12-6x+x+3-7=0
-7x=-16
x=16/7