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актриса235689
@актриса235689
July 2022
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Решите уравнение 2х(х-8)= -х-18.
Решите уравнение х^4-2х^2-8=0.
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Kixcertborn2
Verified answer
2x(x-8)= -x-18.
2x^2-16x=-x-18
2x^2-15x+18=0
D=(-15)^2-4*2*18=225-144=81=9^2
x=(15
±9)/2
x
₁=6
x₂=3/2
==========================================================
х^4-2х^2-8=0.
x^2=a
a^2-2a-8=0
D=(-2)^2-4*1*(-8)=4+32=36=6^2
a=(2
±6)/2
a
₁=4
a₂=-2
Возвращаемся
x²=4 x=±2 x=2, x=-2
x²=-2 x=±√-2 x∉R
Ответ:
x
₁
=2
x
₂
=-2
11 votes
Thanks 13
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Answers & Comments
Verified answer
2x(x-8)= -x-18.2x^2-16x=-x-18
2x^2-15x+18=0
D=(-15)^2-4*2*18=225-144=81=9^2
x=(15±9)/2
x₁=6
x₂=3/2
==========================================================
х^4-2х^2-8=0.
x^2=a
a^2-2a-8=0
D=(-2)^2-4*1*(-8)=4+32=36=6^2
a=(2±6)/2
a₁=4
a₂=-2
Возвращаемся
x²=4 x=±2 x=2, x=-2
x²=-2 x=±√-2 x∉R
Ответ:x₁=2
x₂=-2