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rimmabuketova
@rimmabuketova
July 2022
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Решите уравнение 2sinx+|sinx|=sin2x
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ggjd
2sinx=sin2x
2sinx=2sinxcosx
2sinx(cosx-1)=0
sinx=0 cosx=1
x=(Пи)n x=2(Пи)n, n принадлежит Z
Ответ: x=(Пи)n, n принадлежит Z
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rimmabuketova
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Answers & Comments
2sinx=2sinxcosx
2sinx(cosx-1)=0
sinx=0 cosx=1
x=(Пи)n x=2(Пи)n, n принадлежит Z
Ответ: x=(Пи)n, n принадлежит Z