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MacTy
@MacTy
July 2022
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решите уравнение (2x-1)^4-x^2=0
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sangers1959
Verified answer
(2x-1)⁴-x²=0
((2x-1)²-x)((2x-1)²+x)=0
(2x-1)²-x=0 4x²-4x+1-x=0 4x²-5x+1=0 D=9 x₁=1 x₂=0,25
(2x-1)²+x=0 4x²-4x+1+x=0 4x²-3x+1=0 D=-7 Уравнение решения не имеет.
Ответ: x₁=1 x₂=0,25.
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Answers & Comments
Verified answer
(2x-1)⁴-x²=0((2x-1)²-x)((2x-1)²+x)=0
(2x-1)²-x=0 4x²-4x+1-x=0 4x²-5x+1=0 D=9 x₁=1 x₂=0,25
(2x-1)²+x=0 4x²-4x+1+x=0 4x²-3x+1=0 D=-7 Уравнение решения не имеет.
Ответ: x₁=1 x₂=0,25.