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milashka99a
@milashka99a
August 2022
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решите уравнение:
2.(x-4)(4x-3)+3=0
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nafanya2014
Verified answer
(x-4)(4x-3)+3=0
4х²-16х-3х+12+3=0
4х²-19х+15=0
D=(-19)²-4·4·15=361-240=121=11²
x₁=(19-11)/8=1 или х₂=(19+11)/8=3,75
Ответ. 1 ; 3,75
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Answers & Comments
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(x-4)(4x-3)+3=04х²-16х-3х+12+3=0
4х²-19х+15=0
D=(-19)²-4·4·15=361-240=121=11²
x₁=(19-11)/8=1 или х₂=(19+11)/8=3,75
Ответ. 1 ; 3,75