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EiBrown
@EiBrown
July 2022
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Решите уравнение:
(2x^2+2x-4)^2 = (x^2+2x-1)^2
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Answers & Comments
армения20171
(2x²+2x-4)²=(x²+2x-1)²
(2x²+2x-4+x²+2x-1)(2x²+2x-4-x²-2x+1)=0
(3x²+4x-5)((x²-3)=0
1)3x²+4x-5=0
D=16+60=84=4*21
x=(-4±2√21)/6=(-2±√21)/3
2)x²-3=0
x²=3
x=±√3
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Answers & Comments
(2x²+2x-4+x²+2x-1)(2x²+2x-4-x²-2x+1)=0
(3x²+4x-5)((x²-3)=0
1)3x²+4x-5=0
D=16+60=84=4*21
x=(-4±2√21)/6=(-2±√21)/3
2)x²-3=0
x²=3
x=±√3