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Ангел0210
@Ангел0210
July 2022
2
4
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решите уравнение: 37x=259; 252:y=21; z:18 =6; 14(p-30)=630; (38+b)•12=840; (43-s)•17=289
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MilashkaYuliya
1)37х=259х=259÷37х=72)252÷у=21у=252÷21у=123)z÷18=6z=18×6z=1084)14 (p-30)=63014p-420=63014p=1050p=755)(38+b)+12=840456+12b=84012b=384b=326)(43-s)×17=289731-17s=28917s=442s=26
3 votes
Thanks 8
aleksandruklili
37х=259
х=7
252:у=21
у=252:21
у=12
z^18=6
z=18*6
z=108
14(р-30)=630
14р-420=630
14р=630+420
14р=1050
р=1050:14
р=75
(38+ь)*12=840
456+12ь=840
12ь=840-456
12ь=384
ь=384:12
ь=32
(43-s)*17=289
731-17s=289
-17s=731-289
-17s=442
s=442^17
s=26
4 votes
Thanks 7
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Answers & Comments
х=7
252:у=21
у=252:21
у=12
z^18=6
z=18*6
z=108
14(р-30)=630
14р-420=630
14р=630+420
14р=1050
р=1050:14
р=75
(38+ь)*12=840
456+12ь=840
12ь=840-456
12ь=384
ь=384:12
ь=32
(43-s)*17=289
731-17s=289
-17s=731-289
-17s=442
s=442^17
s=26