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janadinama
@janadinama
July 2022
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решите уравнение 3х^2+х-4=0
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D=b^2-4ac; a=3;b=1;c=(-4)
D=1-4×3×(-4)=1+48= 49
х1=(-1-7)/6= -8/6= -4/3
х2=(-1+7)/6=1
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Answers & Comments
D=1-4×3×(-4)=1+48= 49
х1=(-1-7)/6= -8/6= -4/3
х2=(-1+7)/6=1