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chepurko2014
@chepurko2014
July 2022
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Решите уравнение (3+i)z=2-3i
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ShirokovP
Verified answer
Z = (2 - 3i)/(3 + i)
z = (2 - 3i)(3 - i) / (3 + i)( 3 - i)
z = (6 - 2i - 9i + 3i^2) / (9 - i^2)
z = (6 - 11i - 3) / (9 + 1)
z = (3 - 11i)/10
z = 3/10 - 11i/10
z = 0,3 - 1,1i
2 votes
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Answers & Comments
Verified answer
Z = (2 - 3i)/(3 + i)z = (2 - 3i)(3 - i) / (3 + i)( 3 - i)
z = (6 - 2i - 9i + 3i^2) / (9 - i^2)
z = (6 - 11i - 3) / (9 + 1)
z = (3 - 11i)/10
z = 3/10 - 11i/10
z = 0,3 - 1,1i