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кубышка
@кубышка
August 2022
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решите уравнение 3x4-13x2+4=0
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Den4ik90
3x4-13x2+4=0
x2=t
3t2-13t+4=0
d=169-48=121
t1=(13+11)/6=4
t2=(13-11)/6=1/3
x2=4
x1=2
x2=-2
x2=1/3
x3=корень из 1/3
x4= корень из -1/3
Ответ:2;-2;-1/3;1/3
8 votes
Thanks 19
amiiga
X2=t
3t²-13t+4=0
D=b²-4ac=169-48=121 √D=11
t1=13+11/6=4
t2=13-11/6=2/6=1/3
так как x²=t⇒
x²=4
x1=+2
x2=-2
x²=1/3
x1=√1/3
x2=-√1/3
7 votes
Thanks 14
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Answers & Comments
x2=t
3t2-13t+4=0
d=169-48=121
t1=(13+11)/6=4
t2=(13-11)/6=1/3
x2=4
x1=2
x2=-2
x2=1/3
x3=корень из 1/3
x4= корень из -1/3
Ответ:2;-2;-1/3;1/3
3t²-13t+4=0
D=b²-4ac=169-48=121 √D=11
t1=13+11/6=4
t2=13-11/6=2/6=1/3
так как x²=t⇒
x²=4
x1=+2
x2=-2
x²=1/3
x1=√1/3
x2=-√1/3