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happylenka
@happylenka
August 2022
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Решите уравнение: 4sin^3 (2x)=1
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antenor
sin^3(2x)=1/4
sin(2x)=4^(-1/3)
2x=(-1)^n*arcsin(4^(-1/3))+
πn,где n∈Z
x=(-1)^n*arcsin(4^(-1/3)/2+
π/2 *n,где n∈Z
1 votes
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Answers & Comments
sin(2x)=4^(-1/3)
2x=(-1)^n*arcsin(4^(-1/3))+πn,где n∈Z
x=(-1)^n*arcsin(4^(-1/3)/2+π/2 *n,где n∈Z