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aleksandragars
@aleksandragars
July 2022
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решите уравнение (4x-1)^2-(4x-1)-12=0
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Kixcertborn2
Verified answer
(4x-1)^2-(4x-1)-12=0
16x^2-8x+1-4x+1-12=0
16x^2-12x-10=0
2(8x^2-6x-5)=0
2(8x^2+4x-10x-5)=0
2(4x*(2x+1)-5(2x+1))=0
2(4x-5)*(2x+1)=0
(
4x-5)*(2x+1)=0
4x-5=0 x1=5/4
2x+1=0 x2=-(1/2)
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mmb1
Verified answer
(4x-1)^2-(4x-1)-12=0
4x-1=t
t
²-t-12=0
D=1+48=49
t₁₂=(1+-7)/2= 4 -3
t₁=4 4x-1=4 4x=5 x=5/4
t₂=-3 4x-1=-3 4x=-2 x=-1/2
0 votes
Thanks 0
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Answers & Comments
Verified answer
(4x-1)^2-(4x-1)-12=016x^2-8x+1-4x+1-12=0
16x^2-12x-10=0
2(8x^2-6x-5)=0
2(8x^2+4x-10x-5)=0
2(4x*(2x+1)-5(2x+1))=0
2(4x-5)*(2x+1)=0
(4x-5)*(2x+1)=0
4x-5=0 x1=5/4
2x+1=0 x2=-(1/2)
Verified answer
(4x-1)^2-(4x-1)-12=04x-1=t
t²-t-12=0
D=1+48=49
t₁₂=(1+-7)/2= 4 -3
t₁=4 4x-1=4 4x=5 x=5/4
t₂=-3 4x-1=-3 4x=-2 x=-1/2