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khramegorov
@khramegorov
June 2022
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Решите уравнение 4x^4+5x^2-3=0
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berikovadina
^это чтокакой это символ:
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khramegorov
Типо 4x в четвертой степени и тд
GSidrat
4х^4+5х^2-3=0
х^2=у
4у^2+5у-3=0
D=b^2-4ac=5^2-4*4*(-3)=25+48=73
y1=(-b+-√d)/2a=(-5+-√73)/2*4=(-5+-√73)/8
x^2=(√-5+-√73)/8
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Answers & Comments
х^2=у
4у^2+5у-3=0
D=b^2-4ac=5^2-4*4*(-3)=25+48=73
y1=(-b+-√d)/2a=(-5+-√73)/2*4=(-5+-√73)/8
x^2=(√-5+-√73)/8