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always4
@always4
July 2022
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решите уравнение (5x-4)(6x+3)=0
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нлоо
(5х-4)(6х+3)=0
5x-4=0 или 6x+3=0
5x=4 6x=-3
x=4/5 x=-1/2
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Эксперт5
Verified answer
(5x-4)(6x+3)=0
30x^2−9x−12=0
D = b^2 - 4 * a * c =
(-9)^2 - 4 * (30) * (-12) = 1521
Т.к. D > 0, то уравнение имеет два корня.
х первое= 4/5
х второе = -1/2
0 votes
Thanks 0
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Answers & Comments
5x-4=0 или 6x+3=0
5x=4 6x=-3
x=4/5 x=-1/2
Verified answer
(5x-4)(6x+3)=030x^2−9x−12=0
D = b^2 - 4 * a * c =
(-9)^2 - 4 * (30) * (-12) = 1521
Т.к. D > 0, то уравнение имеет два корня.
х первое= 4/5
х второе = -1/2