решите уравнение (8 класс):
9-16х^2=0;
5х^2-16x+3=0;
х-5=х^2-25;
(х+1)^2=(2х-1)^2
9-16х^2=0;
5х^2-16x+3=0;
х-5=х^2-25;
(х+1)^2=(2х-1)^2
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Answers & Comments
x^2=9/16
x1=3/4
x2=-3/4
2) 5x^2-16x+3=0
D=(-16)^2-4*5*3=256-60=196
x1=(16-14)/2*5=0.2
x2=(16+14)/2*5=30/10=3
3) x-5=x^2-25
x^2-x-20=0
D=1-4*(-20)=1+80=81
x1=(1+9)/2=10/2=5
x2=(1-9)/2=-8/2=-4
4) (х+1)^2=(2х-1)^2
x^2+2x+1=4x^2-4x+1
3x^2-6x=0
3x(x-2)=0
3x=0, x1=0
x-2=0, x2=2