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mrmilenkovich
@mrmilenkovich
July 2022
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Решите уравнение 99 баллов
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DisLine
Verified answer
Формулы приведения:
sin (3π-x)= sin x
sin (π/2-x)= cos x
Подставим:
2sin x - 3cos x=0;
2sin x=3cos x |:cos x;
2tg x =3;
tg x = 3/2;
x=arctg (3/2) +πn, n принадлежит множеству Z
1 votes
Thanks 1
AnonimusPro
Verified answer
2sin(3pi)*cos(x)-2sin(x)*cos(3pi)-3cos(x)=0
2sin(2pi+pi)*cos(x)-2sin(x)*cos(2pi+pi)-3cos(x)=0
2sin(pi)*cos(x)-2sin(x)*cos(pi)-3cos(x)=0
2*0*cos(x)-2sin(x)*(-1)-3cos(x)=0
2sin(x)-3cos(x)=0
делим на cos(x):
2sin(x)/cos(x)-3=0
2tg(x)=3
tg(x)=3/2
x=arctg(3/2)+pi*n
Ответ: x=arctg(3/2)+pi*n
2 votes
Thanks 1
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Answers & Comments
Verified answer
Формулы приведения:sin (3π-x)= sin x
sin (π/2-x)= cos x
Подставим:
2sin x - 3cos x=0;
2sin x=3cos x |:cos x;
2tg x =3;
tg x = 3/2;
x=arctg (3/2) +πn, n принадлежит множеству Z
Verified answer
2sin(3pi)*cos(x)-2sin(x)*cos(3pi)-3cos(x)=02sin(2pi+pi)*cos(x)-2sin(x)*cos(2pi+pi)-3cos(x)=0
2sin(pi)*cos(x)-2sin(x)*cos(pi)-3cos(x)=0
2*0*cos(x)-2sin(x)*(-1)-3cos(x)=0
2sin(x)-3cos(x)=0
делим на cos(x):
2sin(x)/cos(x)-3=0
2tg(x)=3
tg(x)=3/2
x=arctg(3/2)+pi*n
Ответ: x=arctg(3/2)+pi*n