Решите уравнение:
а) 11 + 3х = 66 + 4х;
б) (4 – х) + 2 (х – 3) = –13;
в) –3 (3у + 1) – 12 = 12.
а) 11 + 3х = 66 + 4х;
б) (4 – х) + 2 (х – 3) = –13;
в) –3 (3у + 1) – 12 = 12.
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Answers & Comments
-х= 55
х=-55
б) (4-х)+2х-6=-13
4-х+2х-6=-13
х=-10
в) -9у-3-12=12
-9у=27
у=- 3