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собака508
@собака508
August 2022
2
4
Report
Решите уравнение:
а) 16х^2-(4х-5)^2=15
б) х(х+3)-(х-1)^2=4
в)(2х+3)^2-(2х-3)^2=48
15б
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n1982
..............................,
1 votes
Thanks 1
niktory
а) 16х^2-(4х-5)^2=15
16x^2-(16x^2-40x+25)=15
16x^2-16x^2+40x-25=15
40х-25=15
40х=40
х=1
б) х(х+3)-(х-1)^2=4
x^2+3x-(x^2-2x+1)=4
x^2+3x-x^2+2x-1=4
3x+2x-1=4
5x-1=4
5x=5
x=1
в) (2х+3)^2-(2х-3)^2=48
4x^2+12x+9-(4x^2-12x+9)=48
12x+9+12x-9=48
24x=48
x=48:24
x=2
0 votes
Thanks 1
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Answers & Comments
16x^2-(16x^2-40x+25)=15
16x^2-16x^2+40x-25=15
40х-25=15
40х=40
х=1
б) х(х+3)-(х-1)^2=4
x^2+3x-(x^2-2x+1)=4
x^2+3x-x^2+2x-1=4
3x+2x-1=4
5x-1=4
5x=5
x=1
в) (2х+3)^2-(2х-3)^2=48
4x^2+12x+9-(4x^2-12x+9)=48
12x+9+12x-9=48
24x=48
x=48:24
x=2