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EXOMAN
@EXOMAN
July 2022
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Решите уравнение а) 2cos^2х – 1 = 0;
б) 3sin2х - √3*cos2x = 0
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Решите уравнение а) 2cos^2х – 1 = 0;
б) 3sin2х - √3*cos2x = 0
а) 2cos^2х – 1 = 0;
1)cosх=-1/√2 2) cosх=1/√2
x=π/4+(π/2)n, n∈Z
б) 3sin2х - √3*cos2x = 0
tg2x=(√3)/3 ⇔ 2x=π/6+πn, n∈Z ·⇔ x=π/12+
πn/2, n
∈
Z
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Решите уравнение а) 2cos^2х – 1 = 0;б) 3sin2х - √3*cos2x = 0
а) 2cos^2х – 1 = 0;
1)cosх=-1/√2 2) cosх=1/√2
x=π/4+(π/2)n, n∈Z
б) 3sin2х - √3*cos2x = 0
tg2x=(√3)/3 ⇔ 2x=π/6+πn, n∈Z ·⇔ x=π/12+πn/2, n∈Z