Ответ:
Объяснение:
a) (3х – 2)2 – (3х – 4) (4 + 3х) = 0
6x - 4 - ( 9x^2 - 16)=0
6x - 4 - 9x^2 + 16=0
6x + 12 - 9x^2=0. /3
2x + 4 - 3x^2=0
-3x^2 + 2x +4 =0
3x^2 - 2x -4 =0
D= 4 - 4 × 3×(-4) =4+ 48= 52
x1,x2=2±√52 / 6
x1, x2 = 2±2√13 / 6
x1=2(1+√13)/6 = (1+√13)/3
x2=2(1-√13)/6 = (1-√13)/3
б)25 × y^2 - 64 =0
(5y-8) (5y+8)=0
5y-8 =0
5y=8
y= 8/5=1 3/5
5y+8 = 0
5y=-8
y= - 8/5 = - 1 3/5
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Answers & Comments
Ответ:
Объяснение:
a) (3х – 2)2 – (3х – 4) (4 + 3х) = 0
6x - 4 - ( 9x^2 - 16)=0
6x - 4 - 9x^2 + 16=0
6x + 12 - 9x^2=0. /3
2x + 4 - 3x^2=0
-3x^2 + 2x +4 =0
3x^2 - 2x -4 =0
D= 4 - 4 × 3×(-4) =4+ 48= 52
x1,x2=2±√52 / 6
x1, x2 = 2±2√13 / 6
x1=2(1+√13)/6 = (1+√13)/3
x2=2(1-√13)/6 = (1-√13)/3
б)25 × y^2 - 64 =0
(5y-8) (5y+8)=0
5y-8 =0
5y=8
y= 8/5=1 3/5
5y+8 = 0
5y=-8
y= - 8/5 = - 1 3/5