Решите уравнение:
a) (4x - 1)4 - 8( 4x-1)2 - 9= 0
б) (x2 + 3x +1)(x2+ 3x+3) = -1
a) (4x - 1)4 - 8( 4x-1)2 - 9= 0 16x - 4 - 64x+16 - 9= 0 48х-3 = 0 х = 1/16
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a) (4x - 1)4 - 8( 4x-1)2 - 9= 0
16x - 4 - 64x+16 - 9= 0
48х-3 = 0
х = 1/16