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koektonezharit
@koektonezharit
August 2022
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Решите уравнение ax+3x-2a2-6a=0 лля любого значения параметра a
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sangers1959
Verified answer
Ax+3x-2a²-6a=0
x(a+3)-(2a²+6a)=0
x(a+3)-2(a+3)=0
(a+3)(x-2)=0
x-2=0
x=2 при a∈(-∞;-3)U(-3;+∞)
x∈(-∞;+∞) при а=-3.
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sangers1959
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Answers & Comments
Verified answer
Ax+3x-2a²-6a=0x(a+3)-(2a²+6a)=0
x(a+3)-2(a+3)=0
(a+3)(x-2)=0
x-2=0
x=2 при a∈(-∞;-3)U(-3;+∞)
x∈(-∞;+∞) при а=-3.