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ВНирване
@ВНирване
August 2022
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Решите уравнение: cos3х+ cos2х= sin5х
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sedinalana
Verified answer
2сos(5x/2)cos(x/2)-2sin(5x/2)cos(5x/2)=0
2cos(5x/2)*(cos(x/2)-sin(5x/2))=0
cos(5x/2)=0⇒5x/2=π/2+πn⇒x=π/5+2πn/5,n∈z
cos(x/2)-sin(5x/2)=0
cos(x/2)-cos(π/2-5x/2)=0
-2sin(3x/2-π/4)sin(-x+π/4)=0
2sin(3x/2-π/4)sin(x-π/4)=0
sin(3x/2-π/4)=0⇒3x/2-π/4=πk⇒3x/2=π/4+πk⇒x=π/6+2πk/3,k∈z
sin(x-π/4)=0⇒x-π/4=πm⇒x=π/4+πm,m∈z
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Answers & Comments
Verified answer
2сos(5x/2)cos(x/2)-2sin(5x/2)cos(5x/2)=02cos(5x/2)*(cos(x/2)-sin(5x/2))=0
cos(5x/2)=0⇒5x/2=π/2+πn⇒x=π/5+2πn/5,n∈z
cos(x/2)-sin(5x/2)=0
cos(x/2)-cos(π/2-5x/2)=0
-2sin(3x/2-π/4)sin(-x+π/4)=0
2sin(3x/2-π/4)sin(x-π/4)=0
sin(3x/2-π/4)=0⇒3x/2-π/4=πk⇒3x/2=π/4+πk⇒x=π/6+2πk/3,k∈z
sin(x-π/4)=0⇒x-π/4=πm⇒x=π/4+πm,m∈z