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sven76crew
@sven76crew
July 2022
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Решите уравнение: cos3x cosx + sin3x sinx = 1
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aleks41
Cos3x·cosx=0.5(cos2x+cos4x).
sin3x·sinx =0.5(cos2x-cos4x).
0,5(cos2x+cos4x)+0,5(cos2x-cos4x)=1.
cos 2x=1.
2х=0°+2πn.
х=πn.
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Answers & Comments
sin3x·sinx =0.5(cos2x-cos4x).
0,5(cos2x+cos4x)+0,5(cos2x-cos4x)=1.
cos 2x=1.
2х=0°+2πn.
х=πn.