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2847000
@2847000
July 2022
2
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Решите уравнение
cos5x=cos3x cos2x
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dobryajalizka
Cos5x=cos3x*cos2x
cos5x=(cos5x+cosx)/2
cos5x+cosx=2cos5x
cosx-cos5x=0
2sin2x*sin3x=0
sin2x=0 sin3x=0
2x=πk 3x=πn
x1=πk/2
x2=πn/3
2 votes
Thanks 5
leshik70
Соs(3x+2x)=co3xcos2x
cos3xcos2x-sin3xsin2x-cos3xcos2x=0
-sin3xsin2x=0
sin3x=0 или sin2x=0
3x= πn,n∈Z 2x=πk, k∈Z
x=
x=
1 votes
Thanks 2
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Answers & Comments
cos5x=(cos5x+cosx)/2
cos5x+cosx=2cos5x
cosx-cos5x=0
2sin2x*sin3x=0
sin2x=0 sin3x=0
2x=πk 3x=πn
x1=πk/2 x2=πn/3
cos3xcos2x-sin3xsin2x-cos3xcos2x=0
-sin3xsin2x=0
sin3x=0 или sin2x=0
3x= πn,n∈Z 2x=πk, k∈Z
x= x=