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peterburg1
@peterburg1
July 2022
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решите уравнение cosx=co3x пожалуйстаааа
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решите уравнение cosx=co3x
cosx-co3x=0
cos(α) – cos(β) = –2sin((α+β)/2)sin((α–β)/2)
cosx-co3x=-2sin((x+3x)/2)sin((x–3x)/2)=-2sin(2x)sin(-x)=2sin(2x)sin(x)=0 ⇔
1)sin(2x)=0 2x=πn,n∈Z x=πn/2, n∈Z
2)sin(x)=0 x=πn,n∈Z x=πn, n∈Z
или x=πn/2, n∈Z
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решите уравнение cosx=co3xcosx-co3x=0
cos(α) – cos(β) = –2sin((α+β)/2)sin((α–β)/2)
cosx-co3x=-2sin((x+3x)/2)sin((x–3x)/2)=-2sin(2x)sin(-x)=2sin(2x)sin(x)=0 ⇔
1)sin(2x)=0 2x=πn,n∈Z x=πn/2, n∈Z
2)sin(x)=0 x=πn,n∈Z x=πn, n∈Z
или x=πn/2, n∈Z