Решите уравнение f ' (x)=0, при f(x)=x-cos²x
1+2cos x sinx=0
1+sin (2x)=0
sin2x=-1
2x=-pi/2 +2pin
x= -pi/4 +pin
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1+2cos x sinx=0
1+sin (2x)=0
sin2x=-1
2x=-pi/2 +2pin
x= -pi/4 +pin