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MandarinBlin
@MandarinBlin
August 2022
2
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решите уравнение (х-2)×корень(х-2)=2х+5
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Evgenia4836
Verified answer
Решение во вложении:
0 votes
Thanks 1
армения20171
(x-2)√(x-2)=2x+5
x-2≥0;x≥2 это ОДЗ
((x-2)√(x-2))²=(2x+5)²
(x-2)²(x-2)=4x²+20x+25
(x-2)³=4x²+20x+25
x³-6x²+12x-8-4x²-20x-25=0
x³-10x²-8x-33=0
x³-11x²+x²-11x+3x-33=0
x²(x-11)+x(x-11)+3(x-11)=0
(x-11)(x²+x+3)=0
1)x-11=0;x=11
2)x²+x+3=0
D=1-12=-11<0
x€∅
ответ 11
1 votes
Thanks 1
MandarinBlin
что вы делаете после x^3-2x^2-8x-33=0
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Answers & Comments
Verified answer
Решение во вложении:
x-2≥0;x≥2 это ОДЗ
((x-2)√(x-2))²=(2x+5)²
(x-2)²(x-2)=4x²+20x+25
(x-2)³=4x²+20x+25
x³-6x²+12x-8-4x²-20x-25=0
x³-10x²-8x-33=0
x³-11x²+x²-11x+3x-33=0
x²(x-11)+x(x-11)+3(x-11)=0
(x-11)(x²+x+3)=0
1)x-11=0;x=11
2)x²+x+3=0
D=1-12=-11<0
x€∅
ответ 11