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merkulova00322
@merkulova00322
July 2022
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Решите уравнение (х-3)²=25
(х+4)²=9
(х-6)²=7
(х+2)²=6
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alengood
X²-6x+9=25
x²-6x-16=0
k=-3
D=9+1·16=25
x1=8
x2=-2
x²-12x+36=7
x²-12x+29=0
k=-6
D=36-1·29=7
x1=6+√7
x2=6-√7
x²+4x+4=6
x²+4x-2=6
k=2
D=4+1·2=6
x1=-2+√6
x2=-2-√6
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Answers & Comments
x²-6x-16=0
k=-3
D=9+1·16=25
x1=8
x2=-2
x²-12x+36=7
x²-12x+29=0
k=-6
D=36-1·29=7
x1=6+√7
x2=6-√7
x²+4x+4=6
x²+4x-2=6
k=2
D=4+1·2=6
x1=-2+√6
x2=-2-√6