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Kisya2
@Kisya2
August 2022
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решите уравнение : х (х в квадрате + 2х+1)=2(х+1)
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Эксперт5
Verified answer
X(x²+2x+1)=2(x+1)
x(x+1)²-2(x+1)=0
(x+1)(x(x+1)-2)=0
(x+1)(x²+x-2)=0
(x+1)(x-1)(x+2)=0
x+1=0 ∨ x-1=0 ∨ x+2=0
x₁=-1 x₂=1 x=-2
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Answers & Comments
Verified answer
X(x²+2x+1)=2(x+1)x(x+1)²-2(x+1)=0
(x+1)(x(x+1)-2)=0
(x+1)(x²+x-2)=0
(x+1)(x-1)(x+2)=0
x+1=0 ∨ x-1=0 ∨ x+2=0
x₁=-1 x₂=1 x=-2