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Ulia1681
@Ulia1681
July 2022
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решите уравнение (х+1)(3х+1)=5
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rubilovalex
3x^2+4x+1-5=0; 3x^2+4x-4=0; D=4^2-4*3*(-4)=16+48=64; x1=(-4-8)/6, x2=(-4+8)/6. x1= -2, x2=2/3. Ответ: x1= -2, x2=2/3.
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MrCalling
(X+1)(3x+1)=5
3X^2+x+3x+1=5
3x^2+4x-4=0
D=16+4*3*4=64
X1=(-4+8)/6=2/3
X2=(-4-8)/6=-2
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Answers & Comments
3X^2+x+3x+1=5
3x^2+4x-4=0
D=16+4*3*4=64
X1=(-4+8)/6=2/3
X2=(-4-8)/6=-2