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sviet2015
@sviet2015
August 2022
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решите уравнение (х^2+y^2+y)^2=х^2+y^2,при у =0
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ShirokovP
Verified answer
(x^2 + 0^2 + 0)^2 = x^2 + 0^2
(x^2)^2 = x^2
(x^2)^2 - x^2 = 0
(x^2 - x)(x^2 + x) = 0
x(x - 1)*x*(x + 1) = 0
x^2 *(x - 1)(x + 1) = 0
1) x^2 =0 ==> x1 = 0
2) x - 1 = 0 ==> x2 = 1;
3) x + 1 = 0 ==> x3 = - 1
ОТВЕТ
- 1; 0 ; 1
3 votes
Thanks 0
sviet2015
Спасибо,выручил.
Masnavichemist
аха н,з,ч!
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Answers & Comments
Verified answer
(x^2 + 0^2 + 0)^2 = x^2 + 0^2(x^2)^2 = x^2
(x^2)^2 - x^2 = 0
(x^2 - x)(x^2 + x) = 0
x(x - 1)*x*(x + 1) = 0
x^2 *(x - 1)(x + 1) = 0
1) x^2 =0 ==> x1 = 0
2) x - 1 = 0 ==> x2 = 1;
3) x + 1 = 0 ==> x3 = - 1
ОТВЕТ
- 1; 0 ; 1