Ответ:
х(х+1) - (х-2)(х-3) = 4
x² + x - (x²- 3x - 2x + 6) = 4
x² + x - (x² - 5x + 6) = 4
x² + x - x² + 5x - 6 = 4
6x - 6 = 4
6x = 4 + 6
6x = 10
x =
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Ответ:
х(х+1) - (х-2)(х-3) = 4
x² + x - (x²- 3x - 2x + 6) = 4
x² + x - (x² - 5x + 6) = 4
x² + x - x² + 5x - 6 = 4
6x - 6 = 4
6x = 4 + 6
6x = 10
x =