решите уравнение:
х(х^2-2)=х^3+8
(х+7)(х-7)-(х-3)^2=53
7х^2=(2х+1)^2+3х^2-5
(х+3)(х-2)-(х-3)(х+2)-5=6х-7
х^3+2х^2-9х-18=0
х(х^2-2)=х^3+8
(х+7)(х-7)-(х-3)^2=53
7х^2=(2х+1)^2+3х^2-5
(х+3)(х-2)-(х-3)(х+2)-5=6х-7
х^3+2х^2-9х-18=0
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Answers & Comments
х(х^2-2)=х^3+8
x^3 - 2x = x^3 + 8
x^3 - x^3 - 2x - 8 = 0
-2x - 8 = 0 | : 1
2x + 8 = 0
2x = -8
x = -8/2 = -4
Ответ : -4
2)
(х+7)(х-7)-(х-3)^2=53
x^2 - 49 - x^2 + 6x - 9 - 53 = 0
6x - 111 = 0
6x = 111
x = 111/6
7х^2=(2х+1)^2+3х^2-5
(2х+1)^2+3х^2-5 = 7х^2
4x^2 + 4x + 1 + 3x^2 - 5 - 7x^2 = 0
4x - 4 = 0
4x = 4
x = 1
Ответ : 1
(х+3)(х-2)-(х-3)(х+2)-5=6х-7
x^2 - 2x + 3x - 6 - x^2 - 2x + 3x + 6 = 6x - 7
2x = 6x - 7
-4x = - 7
x = 7/4