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denimusienk
@denimusienk
November 2021
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Решите уравнение методом разложения на множители
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Mary88888
Cos7x+cosx=0
2cos4xcos3x=0
1) cos4x=0;4x=π/2+πn;x=π/8+πn/4,n∈Z
2) cos3x=0;3x=π/2+πk;x=π/6+πk/3,k∈Z.
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Answers & Comments
2cos4xcos3x=0
1) cos4x=0;4x=π/2+πn;x=π/8+πn/4,n∈Z
2) cos3x=0;3x=π/2+πk;x=π/6+πk/3,k∈Z.