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shushukalist
@shushukalist
June 2022
1
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Решите уравнение методом введения новой переменной
(Х+1)(Х-2)(Х+3)(Х-4)=144
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Answers & Comments
srzontmp
(x+3)(x-4) = x^2 - x - 12
(x+1)(x-2)= x^2 - x - 2
(x+1)(x-2) = y
(x+3)(x-4) = y - 10
y(y-10) = 144
y1 = 18
y2 = - 8
x^2 - x - 2 = - 8 -> x^2 - x + 6 = 0 - нет действительных корней
x^2 - x - 2 = 18 -> x^2 - x - 20 =0
x1 = 5, x2 = - 4
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Answers & Comments
(x+1)(x-2)= x^2 - x - 2
(x+1)(x-2) = y
(x+3)(x-4) = y - 10
y(y-10) = 144
y1 = 18
y2 = - 8
x^2 - x - 2 = - 8 -> x^2 - x + 6 = 0 - нет действительных корней
x^2 - x - 2 = 18 -> x^2 - x - 20 =0
x1 = 5, x2 = - 4