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asi1092010
@asi1092010
July 2021
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решите уравнение номер 216
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kateromanenko
15/(a+15)=3/7
15*7=3*(a+15)
105=3a+45
3a=60
a=20
4/5=(60-m)/40
4*40=(60-m)*5
160=300-5m
5m=140
m=28
(5x-7)*12=1/4
4*(5x-7)=12
20x-28=12
20x=40
x=2
1 votes
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Answers & Comments
15*7=3*(a+15)
105=3a+45
3a=60
a=20
4/5=(60-m)/40
4*40=(60-m)*5
160=300-5m
5m=140
m=28
(5x-7)*12=1/4
4*(5x-7)=12
20x-28=12
20x=40
x=2