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Vikusw
@Vikusw
July 2022
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Решите уравнение: (ответ 0,25 и 1)
(2x-1)^4-x^2=0
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NA1966
((2x-1)^2)^2=x^2
(4x^2-4x+1)^2 =x^2
4x^2-4x+1=x
4x^2-5x+1=0 D = 9
x1= 5-3/8= 1\4=0.25
x2= 5+3/8= 1
Ответ: 0,25 и 1
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Answers & Comments
(4x^2-4x+1)^2 =x^2
4x^2-4x+1=x
4x^2-5x+1=0 D = 9
x1= 5-3/8= 1\4=0.25
x2= 5+3/8= 1
Ответ: 0,25 и 1