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LEZENR
@LEZENR
August 2022
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Решите уравнение по тригонометрии
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Dимасuk
Verified answer
Cos²x - 1/2sin2x + cosx = sinx
cos²x - 1/2·2sinxcosx + cosx - sinx = 0
cos²x - sinxcosx + cosx - sinx = 0
cosx(cosx - sinx) + (cosx - sinx) = 0
(cosx + 1)(cosx - sinx) = 0
1) cosx + 1 = 0
cosx = -1
x = π + 2πn, n ∈ Z
2) cosx - sinx = 0
sinx = cosx
tgx = 1
x = π/4 + πk, k ∈ Z
Ответ: x = π + 2πn, n ∈ Z; π/4 + πk, k ∈ Z.
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Answers & Comments
Verified answer
Cos²x - 1/2sin2x + cosx = sinxcos²x - 1/2·2sinxcosx + cosx - sinx = 0
cos²x - sinxcosx + cosx - sinx = 0
cosx(cosx - sinx) + (cosx - sinx) = 0
(cosx + 1)(cosx - sinx) = 0
1) cosx + 1 = 0
cosx = -1
x = π + 2πn, n ∈ Z
2) cosx - sinx = 0
sinx = cosx
tgx = 1
x = π/4 + πk, k ∈ Z
Ответ: x = π + 2πn, n ∈ Z; π/4 + πk, k ∈ Z.