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eminesuleymanova
@eminesuleymanova
July 2022
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решите уравнение. пожалуйста
sin^2 + 2 sinx+ 1=0
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NeZeRAvix
Verified answer
1 votes
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Burzumistr
Пусть y=sinx, тогда
y²+2y+1=0;
Корни:
y1=y2=1.
sinx=1;
x=0±2πn, где n принадлежит Z
0 votes
Thanks 0
Burzumistr
Прошу прощения. Ошибся. y=-1, a x=3π/2....
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Answers & Comments
Verified answer
y²+2y+1=0;
Корни:
y1=y2=1.
sinx=1;
x=0±2πn, где n принадлежит Z