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Nedostupnaya
@Nedostupnaya
July 2022
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Решите уравнение, пожалуйста
(x^2-3x-1)^2=(x^2-4x+1)^2
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BelarussianComrade
Всё решение в прикреплённом файле.
1 votes
Thanks 0
litanalove
если так, как вы решаете, то -3х +4х никак не будет 7х
litanalove
(x²-3x-1)² -(x²-4x+1)² =0
(x²-3x-1 -(x²-4x+1))(x²-3x-1 +(x²-4x+1)) =0
(x²-3x-1-x²+4x-1)(x²-3x-1+x²-4x+1) =0
(x -2)(2x² -7x) =0
x(x -2)(2x -7) =0
x =0,
x -2 =0, x =2
2x -7 =0, 2x =7, x =7/2 =3.5
ответ: x =0, x =2, x =3.5
1 votes
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Answers & Comments
(x²-3x-1 -(x²-4x+1))(x²-3x-1 +(x²-4x+1)) =0
(x²-3x-1-x²+4x-1)(x²-3x-1+x²-4x+1) =0
(x -2)(2x² -7x) =0
x(x -2)(2x -7) =0
x =0,
x -2 =0, x =2
2x -7 =0, 2x =7, x =7/2 =3.5
ответ: x =0, x =2, x =3.5