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Katrin0205
@Katrin0205
September 2021
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решите уравнение пожалуйста
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jay79
В)1/(t-6)+3=10/t
t+3t(t-6)=10(t-6)
t+3t^2-18t=10t-60
3t^2-27t+60=0
t^2-9t+20=0
D=(-9)^2-4*1*20=81-80=1
t(первое)=(9+1)/2=5
t(2)=(9-1)/2=4
г)4/(y-2)-3/y=1/2
8y-6(y-2)=y(y-2)
8y-6y+12=y^2-2y
-y^2+4y+12=0
y^2-4y-12=0
D=(-4)^2-4*1*(-12)=16+48=64
y(1)=(4+8)/2=6
y(2)=(4-8)/2=-2
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Answers & Comments
t+3t(t-6)=10(t-6)
t+3t^2-18t=10t-60
3t^2-27t+60=0
t^2-9t+20=0
D=(-9)^2-4*1*20=81-80=1
t(первое)=(9+1)/2=5
t(2)=(9-1)/2=4
г)4/(y-2)-3/y=1/2
8y-6(y-2)=y(y-2)
8y-6y+12=y^2-2y
-y^2+4y+12=0
y^2-4y-12=0
D=(-4)^2-4*1*(-12)=16+48=64
y(1)=(4+8)/2=6
y(2)=(4-8)/2=-2