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ok1999
@ok1999
September 2021
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Решите уравнение пожалуйста
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nKrynka
Решение
1) (7^x)*(7 + 3) = (2^x)*(2^5 + 3)
(7^x)*10 = (2^x)*35
(7/2)^x = 35/10
(3,5)^x = (3,5)^1
x = 1
2) (5^x) - (1/25)*(5^x) = 2*(2^x) +4*(2^x)
(5^x)*( 1 - 1/25) = (2^x)*(2 + 4)
(5^x)*(24/25) = (2^x)*6
(2/5)^x = 4/25
(2/5)^x = (2/5)^2
x = 2
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Answers & Comments
1) (7^x)*(7 + 3) = (2^x)*(2^5 + 3)
(7^x)*10 = (2^x)*35
(7/2)^x = 35/10
(3,5)^x = (3,5)^1
x = 1
2) (5^x) - (1/25)*(5^x) = 2*(2^x) +4*(2^x)
(5^x)*( 1 - 1/25) = (2^x)*(2 + 4)
(5^x)*(24/25) = (2^x)*6
(2/5)^x = 4/25
(2/5)^x = (2/5)^2
x = 2