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alinkakislyak
@alinkakislyak
August 2022
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krugly1981
( x - 4)^2(x + 10) - 15(x -4) = 0
( x - 4)( (x-4)(x+10) - 15) =0
( x - 4)(x^2 + 6x - 40 - 15) = 0
( x - 4)(x^2 + 6x - 55) = 0
x - 4 = 0
x = 4
x^2 + 6x - 55 =0
D = b^2 - 4ac = 36 + 220 = 256 =16^2
x1 = ( - 6 + 16) / 2 = 5
x2 = ( - 6 - 16) / 2 = - 11
Ответ: уравнение имеет три корня: x1 = 5, x2 = - 11, x3 = 4.
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Gviona
(x-4)^2*(x+10)= 15(x-4)
(x-4)(x-4)(x+10)-15(x-4)=0
(x-4)*[(x-4)(x+10)-15]=0
(x-4)(x^2+10x-4x-40-15)=0
(x-4)(x^2+6x-55)=0
x-4=0; x^2+6x-55=0
1)x-4=0
x=4
2)x^2+6x-55=0
D=6^2-4*(-55)=256=16^2
x1=(-6-16)/2=-11
x2=(-6+16)/2=5
Ответ:{-11; 4; 5}
0 votes
Thanks 0
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Answers & Comments
( x - 4)( (x-4)(x+10) - 15) =0
( x - 4)(x^2 + 6x - 40 - 15) = 0
( x - 4)(x^2 + 6x - 55) = 0
x - 4 = 0
x = 4
x^2 + 6x - 55 =0
D = b^2 - 4ac = 36 + 220 = 256 =16^2
x1 = ( - 6 + 16) / 2 = 5
x2 = ( - 6 - 16) / 2 = - 11
Ответ: уравнение имеет три корня: x1 = 5, x2 = - 11, x3 = 4.
(x-4)(x-4)(x+10)-15(x-4)=0
(x-4)*[(x-4)(x+10)-15]=0
(x-4)(x^2+10x-4x-40-15)=0
(x-4)(x^2+6x-55)=0
x-4=0; x^2+6x-55=0
1)x-4=0
x=4
2)x^2+6x-55=0
D=6^2-4*(-55)=256=16^2
x1=(-6-16)/2=-11
x2=(-6+16)/2=5
Ответ:{-11; 4; 5}