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MariyaMer
@MariyaMer
October 2021
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05101965nalsur
Log₇ x+log₇² 6²=log₇-¹ (2x+6)+log₇48; log₇ x+log₇6+log₇(2x+6)-log₇48=0; log₇ 6x(2x+6)/48 =0; 6x(2x+6)/48=1; 6x(2x+6)=48; x(x+3)=4; x²+3x-4=0; D=25; x₁= -4; x₂=1
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MariyaMer
Там должно получится 1/7 Пересмотрите еще раз пожалуйста. Спасибо
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