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Sori555
@Sori555
August 2022
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Решите уравнение пж (х+1) (х+2)=(х-3) (х+4)
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nichotakogo
Х в кв+ 2х+х+2=х в кв +4х-3х-12
1 votes
Thanks 0
gorshckowashur1
Ответ:
1)способ:решение уравнение:
(x+1)(x+2)-(x-3)(x+4)=0
X^2+2x+x+2-(X^2+4x-3x-12)=0
x^2+3x+2-x^2-x+12=0
2x+14=0
2x=-14
x=-7
2)способ:подбор:
(x+1)(x+2)=(x-3)(x+4)
x=-7
(-7+1)(-7+2)=(-7-3)(-7+4)
-6*(-5)=-10*(-3)
30=30
3 votes
Thanks 1
Sori555
спасибо большое
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Answers & Comments
1)способ:решение уравнение:
(x+1)(x+2)-(x-3)(x+4)=0
X^2+2x+x+2-(X^2+4x-3x-12)=0
x^2+3x+2-x^2-x+12=0
2x+14=0
2x=-14
x=-7
2)способ:подбор:
(x+1)(x+2)=(x-3)(x+4)
x=-7
(-7+1)(-7+2)=(-7-3)(-7+4)
-6*(-5)=-10*(-3)
30=30